On 23/02/12 00:59, Saad Javed wrote:
[CODE]feed = urllib.urlopen(rssPage) #rssPage: address of xml feed
tree = etree.parse(feed)
x = tree.xpath("/rss/channel/item/title/text()")
x = str(x[0])
for tag in tags: #tags is a list of items like hdtv, xvid, 720p etc
x = re.sub(r'\b' + tag + r'\b', '', x)
z = re.sub(r'[^\w\s]', '', x)
y = tree1.xpath("/rss/channel/item/pubDate/text()")
print "%s - %s" %(z.rstrip(), y[0][:16])[/CODE]
Please don;t insert wiki style markers, its just confusing.
Also please use plain text for email otherwise the formatting
tends to get lost.
[CODE]def get_value(feed):
try:
url = urllib2.urlopen(feed)
tree = etree.parse(url)
x = tree.xpath("/rss/channel/item/title/text()")
y = tree.xpath("/rss/channel/item/pubDate/text()")
x = str(x[0])
y = str(y[0][:16])
return x
return y
This will always return x and never y because a return statement
terminates the function. If you want to return both values you need to
put them in the same return statement:
return x,y
If you want to return only one you need to select which
with an if/else.
return x if <some condition> else y
or just
if <some condition>
return x
else
return y
If you prefer.
except SyntaxError:
You should probably not try catching Syntax errors since thats usually a
fault in your code! Instead fix the syntax error.
def del_tag(x):
tags = ['HDTV', 'LOL', 'VTV', 'x264', 'DIMENSION', 'XviD', '720P',
'IMMERSE', '720p', 'X264']
for tag in tags:
x = re.sub(r'\b' + tag + r'\b', '', x)
y = re.sub(r'[^\w\s]', '', x)
You don't return x or y so they get thrown away at the end of the
function. Which makes the whole thing a waste of space...
def main():
a = get_value(rssPage)
b = del_tag(a)
print b
if __name__ == '__main__':
main()[/CODE]
Running this code returns [B]None[/B].
None is the default return value if you do not provide one.
main has no return statement. Neither does del_tag()
Both main and del_tag will therefore return None.
HTH
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
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