I am new to Python and am trying to figure out how to execute Linux
commands via a Python wrapper.
This works
**********************
#this works okay
import subprocess
uname = "uname"
uname_arg = "-a"
subprocess.call([uname,uname_arg])
**********************
But this doesn't.
***********************
#this doesn't work
import subprocess
#perl prog works in real life
perl_prog = "perl perlprog.pl"
perl_prog_h ="-h"
#this is where it breaks
subprocess.call([perl_prog, perl_prog_h])
************************
I get the following error when I run the program
python errorCheck.py
Linux mybox.domain.com 2.6.18-238.9.1.el5 #1 SMP Tue Apr 12 18:10:13
EDT 2011 x86_64 x86_64 x86_64 GNU/Linux
Traceback (most recent call last):
File "errorCheck.py", line 16, in ?
subprocess.call([perl_prog, perl_prog_h])
File "/usr/lib64/python2.4/subprocess.py", line 419, in call
return Popen(*args, **kwargs).wait()
File "/usr/lib64/python2.4/subprocess.py", line 550, in __init__
errread, errwrite)
File "/usr/lib64/python2.4/subprocess.py", line 996, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
any suggestions?
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