Sorry for the double-post.
I don't think I am wrong either. Replace doesn't return a list of words in
the way that my code sample was setup to do.
How would you solve it with replace? Maybe an example prove the point
better.
-Mario
On Wed, Jun 20, 2012 at 4:10 PM, mariocatch <marioca...@gmail.com> wrote:
> Yes, I meant split(). Was a typo :)
>
>
> On Wed, Jun 20, 2012 at 3:56 PM, Prasad, Ramit
> <ramit.pra...@jpmorgan.com>wrote:
>
>> Please always post back to the list.
>>
>> > Nope, strip() was intended so we get a list back instead of a string.
>> Need
>> > the list for iteration down below that.
>>
>> >> > para = paragraph.strip('.').strip(',').strip().split()
>> >> I think you want replace not strip.
>> >>
>> >> See http://docs.python.org/library/stdtypes.html#string-methods
>>
>> No, you are wrong. If you had looked at the link (or tested the code) you
>> would find strip() does not do what you think it does.
>>
>> What do you mean by "we get a list back instead of a string"? strip does
>> not return a list...it returns a string. split is what returns the list
>> for
>> iteration.
>>
>>
>> >>> paragraph = "This paragraph contains words once, more than once, and
>> possibly not at all either. Figure that one out. "
>> >>> para = paragraph.strip('.').strip(',').strip().split()
>> >>> print para
>> ['This', 'paragraph', 'contains', 'words', 'once,', 'more', 'than',
>> 'once,', 'and', 'possibly', 'not', 'at', 'all', 'either.', 'Figure',
>> 'that', 'one', 'out.']
>>
>> Note the inclusion of 'once,' and 'either.' and 'out.'. Use replace to
>> remove
>> punctuation instead and then just compare words. Most probably you want
>> to lower()
>> or upper() the entire paragraph to be thorough, otherwise 'This' and
>> 'this' will
>> be counted separately.
>>
>>
>> Ramit
>>
>>
>> Ramit Prasad | JPMorgan Chase Investment Bank | Currencies Technology
>> 712 Main Street | Houston, TX 77002
>> work phone: 713 - 216 - 5423
>>
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