On Thu, Aug 16, 2012 at 7:33 AM, leon zaat <zaat...@hotmail.com> wrote: > > Tried it with: > openbareruimtenaam = openbareruimtenaam1.decode("UTF-8").encode("cp1252") > but still the complains about the ascii error
Did you also change it for woonplaatsnaam? For example: ~~~~ import locale file_encoding = locale.getpreferredencoding() #e.g. "cp1252" db_encoding = "utf-8" for row in num: openbareruimtenaam1 = row[0].decode(db_encoding) openbareruimtenaam = openbareruimtenaam1.encode(file_encoding) woonplaatsnaam1 = row[0].decode(db_encoding) woonplaatsnaam = woonplaatsnaam1.encode(file_encoding) newrow = [openbareruimtenaam, woonplaatsnaam] verblijfhoofd.writerow(newrow) # Should "woonplaatsnaam1" be assigned to row[1] instead of row[0]? ~~~~ Off -topic comments: Try to avoid cluttering your code with redundant parentheses, unless they make it easier to understand a complex expression. If func() returns a string, you don't need to do "string" + (func()). The extra parentheses are just noise. Use "string" + func(). Also, if you have a long string, use the compiler's implicit string join instead of runtime concatenation. If you have "string1" "string2", the compiler stores "string1string2". You can combine this with a parenthesized multiline expression. For example: ~~~~ sql = ("Select identificatie, hoofdadres, verblijfsobjectgeometrie " "from verblijfsobject where identificatie > '" + hulpIdentificatie) ~~~~ _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor