On Fri, Sep 7, 2012 at 11:32 AM, Dave Angel <d...@davea.name> wrote: > > I'm curious why the docstring says ... timeout = <object object> > but have no clues for you.
socket._GLOBAL_DEFAULT_TIMEOUT is an object(). In other words, it's an "object object". Also, that's not from the docstring but the call signature. The function doesn't have a docstring. _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
