----- Original Message -----
> From: Asokan Pichai <[email protected]>
> To: [email protected]
> Cc:
> Sent: Friday, October 5, 2012 11:06 AM
> Subject: Re: [Tutor] rounding up to the nearest multiple of 8
>
> If you are doing so many times, it may be worth precomputing the padding for a
> given length and adding it by a look up on the length.
>
> For example:
> ------------------------
> SPACE = ' '
> MAX = 1000
> TAB = 8
> paddding = [ SPACE * (n % TAB) for n in range(MAX) ]
>
> .....
> s = padding[len(s)] + s
> .....
> --------------------------
> where s is string to be padded
>
> Asokan Pichai
Good idea! I know that the string values can never exceed 32767 bytes. So when
I combine all the advice I got here, the best way seems to be ver4, using
Eryksun's ver3 to initialize a dictionary:
from timeit import timeit
setup = "from math import ceil; value = 1040 * '*'"
setup += "; " + "padLookup = dict([(i, -8 * (i // -8)) for i in range(1,
32767+1)])"
ver1 = timeit('int(ceil(len(value)/8.0)*8)', setup=setup)
ver2 = timeit('len(value) + (-len(value) % 8)', setup=setup)
ver3 = timeit('-8 * (len(value) // -8)', setup=setup)
ver4 = timeit('padLookup[len(value)]', setup=setup)
print ver1/ver4, ver2/ver4, ver3/ver4, ver4/ver4
Thanks guys!
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