Mark Lawrence wrote:
> On 08/10/2012 17:43, Benjamin Fishbein wrote:
> > I figured out a solution for the question I asked on here.
> > To find the next digit (0-9) in a string, I use:
> > text.find("0" or "1" or "2", etc.......)
> > But is there a more elegant way to do this? The way I found uses a lot of
> > typing.
> >
>
> How about something like:-
>
> for ch in text:
> if ch.isdigit():
> doSomething(ch)
>
> or:-
>
> for ch in text:
> if '0' <= ch <= '9':
> doSomething(ch)
I am not sure that will work very well with Unicode numbers. I would
assume (you know what they say about assuming) that str.isdigit()
works better with international characters/numbers.
>>> '1'.isdigit()
True
>>> '23'.isdigit()
True
>>> '23a'.isdigit()
False
for ch in text:
if ch.isdigit():
# do something
>
>
> If you want to use the offset for any reason use enumerate:-
>
> for i, ch in enumerate(text):
> etc.
>
> --
> Cheers.
>
> Mark Lawrence.
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