Hi Varun,
Thanks for your reply.
I agree the problem is logic - but how can one inspect one number using
if x%2 == 0 and then compare it to two other numbers which should at the
same time be checked for "oddness", just using the basic constructs?
Thanks,
Peter
On 11/22/2012 02:06 PM, Varun Nagpal wrote:
Hi Peter,
The reason why your program is not behaving as it should is not
Pythonic but rather logic.
Instead of giving away the code, I would suggest you revisit the 'and'
conditions.
The program should print the largest odd number i.e. the number which
is largest among all odd numbers.
Instead you are printing the number which is largest AND odd.
--
Varun
On Thu, Nov 22, 2012 at 6:25 PM, Peter O'Doherty
<m...@peterodoherty.net <mailto:m...@peterodoherty.net>> wrote:
Hi list,
Firstly, apologies for the low-level nature of this question -
it's really quite basic but I don't seem to be able to solve it.
I need to write a program that examines 3 variables x, y, z, and
prints the largest odd number. I've tried all sorts of variations
and this is the current version:
x, y, z = 26, 15, 20
if x > y and x > z and x%2 != 0:
print 'x is largest and odd'
elif y > x and y > z and y%2 != 0:
print 'y is largest and odd'
elif z > x and z > y and z%2 != 0:
print 'z is largest and odd'
else:
print 'no odd'
A solution should be possible using only the simple operators and
keywords above, no functions, lists or any other form of
iteration. (It's from p. 16 of Introduction to Computation and
Programming Using Python, and no, it's not "homework"!)
Many thanks,
Peter
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