hello, i have this code from the google fusion table api: (zmgc)☺ python * master 9e4be39 ✗zmgc" Python 2.7.2 (default, Jan 28 2012, 14:53:22) [GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> import csv >>> import urllib2, urllib >>> request_url = 'https://www.google.com/fusiontables/api/query' >>> query = 'SELECT * FROM 3027809' >>> url = "%s?%s" % (request_url, urllib.urlencode({'sql': query})) >>> serv_req = urllib2.Request(url=url) >>> serv_resp = urllib2.urlopen(serv_req) >>> reader = csv.DictReader(serv_resp) >>> for row in reader: ... print row ... {'Name': 'Portugal', 'Contact': 'i...@zeitgeistportugal.org', 'Link': 'http://www.zeitgeistportugal.org/', 'Location': 'Portugal', 'Type': 'Country', 'Icon': '1'} {'Name': 'Porto', 'Contact': 'po...@zeitgeistportugal.org', 'Link': 'http://porto.zeitgeistportugal.org', 'Location': 'Porto, Portugal', 'Type': 'Region', 'Icon': '2'} {'Name': 'Lisboa', 'Contact': 'lis...@zeitgeistportugal.org', 'Link': 'http://lisboa.zeitgeistportugal.org', 'Location': 'Lisbon, Portugal', 'Type': 'Region', 'Icon': '2'} {'Name': '\xd0\x91\xd1\x8a\xd0\xbb\xd0\xb3\xd0\xb0\xd1\x80\xd0\xb8\xd1\x8f', 'Contact': 'zgeis...@gmail.com', 'Link': 'http://thezeitgeistmovement.bg/', 'Location': 'Bulgaria', 'Type': 'Country', 'Icon': '1'}
the table has a mix of charecters: https://www.google.com/fusiontables/DataSource?docid=1epTUiUlv5NQK5x4sgdy1K47ACDTpHH60hbng1qw what will be the correct way to encode the items in each dictionary row? thanks norman -- %>>> "".join( [ {'*':'@','^':'.'}.get(c,None) or chr(97+(ord(c)-83)%26) for c in ",adym,*)&uzq^zqf" ] ) _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor