Phil wrote:
> On 20/03/13 15:09, Mitya Sirenef wrote:
> <cut>
>
>>
>> By the way, you can further simplify it by doing:
>>
>> def histogram2(s):
>> return {c: d.get(c,0)+1 for c in s}
>>
>>
>> That will work in python 3, in python 2 you need:
>>
>> return dict((c: d.get(c,0)+1) for c in s)
>>
>
> Thanks again Mitya, although I'm not sure it's a simplification at my
> present level.
Especially as Mitya's code doesn't work.
>>> {k: v for k, v in [(1, "a"), (2, "b")]}
{1: 'a', 2: 'b'}
is called "dict comprehension", it builds a dict from a list of key-value
pairs. However, there is no way to reference the resulting dict while it is
being built, and that is necessary for a histogram. It is possible to use
dict.update() with a generator expression
>>> d = {}
>>> d.update((c, d.get(c, 0)+1) for c in "abba")
>>> d
{'a': 2, 'b': 2}
but frankly, I don't see how that is better than the for loop.
So as your experience with Python grows you may continue to use a loop or
switch to the standard library's collections.Counter (Python3 only).
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