Thanks!
I defined a function, as you suggested, to call when the button was
clicked. But then I also had to use self.fileDialog from within the
function. Not sure how I could avoid using fileDialog.
I also defined global variable (under the class) and assigned it to the
filename, so I could access it from within the main class.
The following works:
QtCore.QObject.connect(self.toolButton,
QtCore.SIGNAL(_fromUtf8("clicked()")), self.getFileName)
def getFileName(self):
self.fileDialog = QtGui.QFileDialog()
path = self.fileDialog.getOpenFileName()
print(" File Selected: ", path)
self.lineEdit.setText(path)
self.XmlFileName = path
Thanks.
On Mon, May 27, 2013 at 6:01 AM, Matthew Ngaha <chigga...@gmail.com> wrote:
> Sorry for the forward, i forgot to reply to tutor
>
> On Mon, May 27, 2013 at 3:53 AM, Sunitha Misra <sunith...@gmail.com>
> wrote:
>
> > self.fileDialog = QtGui.QFileDialog()
> >
> > QtCore.QObject.connect(self.toolButton,
> > QtCore.SIGNAL(_fromUtf8("clicked()")), self.fileDialog.getOpenFileName)
> >
>
> i think the way youre doing it won't allow you to get the filename as
> you are calling it through a signal.
>
> Things you can do:
>
> 1) dont use self.fileDialog.getOpenFileName as a slot like you are
> doing. Create a function and call it when the toolbar's button is
> clicked, then in that function assign the filename to the return value
> of self.fileDialog.getOpenFileName.
>
> 2) if the only thing your self.fileDialog is doing is responding to
> the toolbar's button, don't create it at all. do what i said in #1 and
> assign a filename variable to the full method of the dialog. What im
> saying is there might be no need to create the self.fileDialog
> instance variable at all.
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