Hey there everybody. I'm new to python and am attempting to teach myself to code while brushing up on my math skills via the problems at projecteuler.net. My solutions thus far have been mostly brute force and this is no exception but I'm having an issue with tackling some iteration in the problem.
Essentially, the problem is to find the largest product of 5 consecutive digits in a random series of numbers. I'm trying to get things working on a very small string to start... my code thus far is below. I begin by getting a list of strings from the original string, only keeping those that are 5 digits long... then those numbers are converted to integers and I get the product with the product function. As you can see, I'm currently doing it only for the string of 12345 stored at strings[0]. If I run that list comprehension as [int(i) for i in strings], I get a new list of all the integers I want; 12345, 23456, 34567, etc... but I can no longer iterate through to multiply them all together... I feel like I need to either pull each individual string apart first and temporarily store it then convert each to an int and get the product or instead, just find a way to iterate through the members of a member of a list... I've read up on a bunch of stuff regarding map(), zip() and enumerate() but none of it seems to be applicable here or maybe I'm misunderstanding it. Once I have a list of products a simple max() should do the trick... or maybe it'd be quicker to compare a to b through each iteration and just keep the larger product rather than creating a giant list of products once I get this step working? Any ideas towards the next step would be much appreciated. str_num = '1234567890' n = 5 strings = [str_num[i:i+5] for i in range(0, len(str_num)) if len(str_num[i:i+5])==5] integers = [int(i) for i in strings[0]] def product(x): p = 1 for n in integers: p*=n return p print product(integers) Thanks in advance! Nick _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor