Jim Mooney wrote:
> dictnumfarkadoodle = listnumfarkadoodle = setnumfarkadoodle = 0
> # Since these are global I'm using words not likely to be duplicated
> until I figure a different way and
> # replace 'farkadoodle' with '' ;')
Name clashes are generally not a problem if
(1) you keep module size manageable and
(2) use descriptive names
I'd suggest
_dictname_index
or
_makeseq_dictname_index
If you want to follow the generator approach you can use default arguments:
>>> from itertools import count
>>> def make_nextname(template):
... return map(template.format, count()).__next__
...
>>> f = make_nextname("farkadoodle{}")
>>> f()
'farkadoodle0'
>>> f()
'farkadoodle1'
>>> f()
'farkadoodle2'
>>> def make_seq(text, type, next_setname=make_nextname("set{}")):
... if type == set:
... print(next_setname(), "=", set(text.split()))
... else:
... raise ValueError("unsupported type")
...
>>> make_seq("alpha beta gamma", set)
set0 = {'alpha', 'beta', 'gamma'}
>>> make_seq("alpha beta gamma", set)
set1 = {'alpha', 'beta', 'gamma'}
>>> make_seq("alpha beta gamma", set)
set2 = {'alpha', 'beta', 'gamma'}
Here's an alternative implementation of make_nextname() which may be easier
to understand:
>>> def make_nextname(template):
... counter = -1
... def nextname():
... nonlocal counter
... counter += 1
... return template.format(counter)
... return nextname
...
>>> f = make_nextname("foo{:03}")
>>> f()
'foo000'
>>> f()
'foo001'
>>> f()
'foo002'
This technique of nesting a function inside another function ("closure") can
also be used on make_seq directly:
def make_make_seq():
set_index = 0
...
def make_seq(text, type):
nonlocal set_index
if type == set:
print("set%s" % set_index, "=", set(text.split()))
set_index += 1
...
return make_seq
make_seq = make_make_seq()
make_seq("a b c", set) # set0 = {'c', 'b', 'a'}
make_seq("a b c", set) # set1 = {'c', 'b', 'a'}
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