On 04/08/13 08:45, Alex Kleider wrote:
sorry, my bad. I forgot to delete that backslash, I meant
re.findall(r"\be\b", "d e f"). Same with the other example.
..but the interesting thing is that the presence or absence of the
spurious back slashes seems not to change the results.
It wouldn't because the backslash says treat the next character as a
literal and if its not a metacharacter its already treated as a literal.
So the \ is effectively a non-operation in that context.
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
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