On Fri, Sep 27, 2013 at 12:04:38PM -0500, Jacqueline Canales wrote:
> composers = ['Antheil', 'Saint-Saens', 'Beethoven', 'Easdale', 'Nielsen']
> x = 'Antheil'
> s = 'Saint-Saens'
> h = 'Beethoven'
> y = 'Easdale'
> k = 'Nielsen'
This is a step backwards from what you had in your first post. You had
the right idea in the first case:
for name in composers:
...
Then you just write a bit of code that checks `name`, rather than a bit
of code to check `x`, another bit of code to check `s`, a third bit of
code to check `h`, a fourth to check `y`, ... What if you had ten
thousand names to check? A for-loop doesn't care if there's one name or
ten thousand names, computers are really good at that sort of tedius
grunt-work.
So, go back to where you started:
for name in composers:
# check whether name starts and ends with the same letter
You want an "if" test. In English:
if first letter of name equals last letter of name:
print name
How do you get the first letter of name?
name[0]
How do you get the last letter of name?
name[-1]
How do you test if two things are equal?
# replace x and y with the first and last letter of name, as above
x == y
is *almost* right. It's not quite what you want, because it is
case-sensitive. 'A' == 'a' will return False, since they are not
precisely them same. You need to make them the same case:
x.lower() == y.lower() # or upper() if you prefer
Putting it all together:
for name in composers:
if **** == **** :
print name
where you have to replace the stars **** with:
first letter of name, converted to lower/upper case
last letter of name, converted to lower/upper case
respectively.
--
Steven
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