On 21/10/13 01:16, Sammy Cornet wrote:
so here is what I have on my script:
OK some comments below...
infile = open('Desktop/unsorted_fruits.docx' ,"r")
outfile = open('Desktop/sorted_fruits.docx', 'w')
You probably want to use txt files.
def find():
index = 0
while index < 26:
list < 26
You haven't created list yet so you can't compare it to anything. But
even if you had this line does nothing useful.
list = ["a", "b", "c", "e", "f", "g", "h", "i", "j", "k", "l",
"m", "n" "o", "p", "q", "r", "s", "t", "u", "v", "w", "z", "y", "z"]
OK, Now you've created list... Although its a bad choice of name because
it hides the list() operation in Python. So you can't now convert things
to lists.
if index[0] == list[0]:
This will fail since index is a number and list is a list. You can't
index a number. I'm not sure what you thought you were comparing?
infile = list + 1
I don't know what you think this does but what it does in practice is
throws away your open file and tries to add 1 to your list which is an
error. You can't add lists and numbers.
print infile
index += 1
infile.close()
outfile.close()
Since you haven't read anything from infile or written anything to
outfile this doesn't achieve much.
I think you need to sit down with a pen and paper and work out how you
would solve this problem then convert that to Python. As it is you have
a long way to go. I also think you may be making the exercise much
harder than it should be. Take a look at the documentation for the
sort() method of lists, that should help.
HTH
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.flickr.com/photos/alangauldphotos
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