On 31.10.2013 04:00, bob gailer wrote:
On 10/30/2013 1:08 PM, Peter O'Doherty wrote:
Hi List,
I know a geometric sequence can be produced by:
series = [2**x for x in range(7)]
But I would like to curtail the sequence before the last element
excedes a certain value.
import itertools
series = [2**x for x in itertools.takewhile(lambda x: 2**x<60, range(7))]
If you first produce an infinite geometric series and take only the
elements up to a certain limit you avoid calculating 2**x twice:
>>> import itertools as it
>>> [x for x in it.takewhile(lambda x: x < 60, (2**x for x in
it.count(0)))]
>>> [1, 2, 4, 8, 16, 32]
Bye, Andreas
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
https://mail.python.org/mailman/listinfo/tutor
