Thanks Bob! :) A list is great idea. I'm just trying to figure out how to print
the number across like a phone number 555-5555 instead of downward. I'm stuck
on that.
5
5
5
Thanks again!
Carmen
Sent from my iPhone
On Oct 31, 2013, at 9:02 AM, "bob gailer" <bgai...@gmail.com> wrote:
> On 10/31/2013 7:52 AM, Carmen Salcedo wrote:
>> I'm not able to post it right now. All I did to the previous program i
>> emailed was changed isalpha() to str.isalpha.
> That does agree with what you posted or got.
>
> The part of your original program that should print a character already is
> print (str.isalpha()
> which raises this exception:
>
> File "N:\Script2.py", line 37, in phoneTranslator
> print(str.isalpha())
> TypeError: descriptor 'isalpha' of 'str' object needs an argument
>
> it should be
>
> print n
>
> Exactly what did you type in response to
> phoneNumber = raw_input ("Please enter the phone number: ")
>
> Note you are not consistent in converting letters:
> elif n == "G" or n == "H" or n == "I":
> n = "4"
> elif n == "J" or n == "K" or n == "L":
> n = 5
> all the numbers should be characters e.g.
> n = "5"
> etc.
>
> There are many ways to get the desired output.
> One is:
> collect the characters in one list, say numberList
> Then use slicing to insert the "-" e.g. numberList[3:3] = "-"
> Then print "".join(numberList)
>
> --
> Bob Gailer
> 919-636-4239
> Chapel Hill NC
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