On 08/11/2013 12:54, donsuni wrote:
Hi, I have a problem in python which is kind of tricky.if i give a sequence of numbers, i should get another sequence of numbers such that the the elements exceeds previous element in the list. For eg seq_num([3,2,5,7])=[3,5,7] since 5 is >3, and 7>5 seq_num([1,2,3,4])=[1,2,3,4] since 2 is >1, and 3>2 and so on seq_num([5,5,5])=[5] seq_num([9,8,7])=[9] and so on without using any inbuilt functions. I tried the following code but it is not incrementing: def seq_num(numlist): n=len(numlist) for i in range(0,n - 1): if numlist[i]>numlist[i+1]: i+=1 return numlist[i]
You've failed to meet the stated requirement as len and range are built-in functions so whether or not the increment occurs is irrelevant.
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