W dniu 2014-01-18 19:20, Pierre Dagenais pisze:
I wish to fill a list called years[] with a hundred lists called year1900[], year1901[], year1902[], ..., year1999[]. That is too much typing of course. Any way of doing this in a loop? I've tried stuff like ("year" + str(1900)) = [0,0] but nothing works. Any solution?
>>> y = 1900 >>> exec('year{} = [0, 0]'.format(y)) >>> year1900 [0, 0] But I still think, that solution with dict with lists is better. -- Best regards, Wiktor Matuszewski | Python 'py{}@wu{}em.pl'.format('wkm', 'ka') | newbie _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor