> This particular case is easily solved:
> 
> def f_lambda(x,pars):
>     return lambda x: poly(x,*pars)
> 
> You let the closure take care of pars and return a function that takes
> exactly one argument x.

Hi Oscar,

This is the opposite of what I am trying to do.  In the example, x represents 
the data and pars represent the parameters I want to determine, so it is the 
pars which I need passed into the “func_code.co_varnames” part of f.

Maybe your suggestion gets me in that direction, but I don’t see how.

Thanks,

Andre
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