On 09/03/14 10:37, Peter Otten wrote:

In this case, I'm fairly sure the line producing this error is::

     image = Image.open("logo.jpg")

And Python is correct, the ‘Image’ type has no ‘open’ attribute. What

There are a few things around called `Image`. The code the OP is trying to
adapt probably uses the Image from the PIL:


Which may lead to another issue since the OP is using Python 3.4.

Is PIL available for any Python 3.x yet?
And especially for 3.4?

--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.flickr.com/photos/alangauldphotos

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