On 09/07/14 02:44, Robert Nanney wrote:
#!/usr/bin/python
#list_test2.py
list1 = [1, 8, 15]
list2 = [2, 9, 16]
list3 = [[3, 4, 5, 6], [10, 11, 12, 13], [17, 18, 19, 20]]
list4 = [7, 14, 21]
one_list = zip(list1, list2, list3, list4)
first_round = [one_list[x][y] for x in range(len(list3)) for y in range(4)]
My first thought is that you are using indexing too much.
The above would be clearer using:
first_round = [tup[x] for tup in one_list for x in range(4)]
second_round = []
for i in first_round:
if not isinstance(i, list):
second_round.append(i)
else:
for x in range(len(i)):
second_round.append(i[x])
and this loop could be
for item in i:
second_round.append(item)
But I think list addition would do the job more easily.
Something like (untested)
second_round += i
While this seems to do the trick, I feel there is probably a
better/more pythonic way to accomplish the same thing.
I agree but I don;t have time right now to figure it out!
But it seems there should be a more straightforward method.
I'm thinking something like
result = []
for L in (list1,list2,list3):
if isinstance(L,list)
result += L
else: result.append(L)
mebbe...
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.flickr.com/photos/alangauldphotos
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