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I guess my higher level question is: "what makes this function iterable?" and the answer appears to be the fact that it uses a generator instead of a return function. Is that correct? -Steve Tenbrink ---------------------------------------------------------------------- Message: 1 Date: Wed, 9 Jul 2014 16:24:46 +0100 From: Ra?l Cumplido <raulcumpl...@gmail.com> To: steve10br...@comcast.net Cc: tutor <tutor@python.org> Subject: Re: [Tutor] How does this work (iterating over a function)? Message-ID: <CAD1Rbrou1hDfxkBeJcB97361uwyNYq8tW7REk=mhuavjenn...@mail.gmail.com> Content-Type: text/plain; charset="utf-8" Hi, A little bit more on this :) Python iterator protocol will call the next() method on the iterator on each iteration and receive the values from your iterator until a StopIteration Exception is raised. This is how the for clause knows to iterate. In your example below you can see this with the next example: >>> gen = fibonacci(3) >>> gen.next() 0 >>> gen.next() 1 >>> gen.next() 1 >>> gen.next() 2 >>> gen.next() Traceback (most recent call last): File "<stdin>", line 1, in <module> StopIteration >>> Thanks, Ra?l -- Ra?l Cumplido -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://mail.python.org/pipermail/tutor/attachments/20140709/ccbbee12/attachment-0001.html>
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