change the line if answera == ["Oslo" or "oslo"]:
to if answera == "Oslo" or answera == "oslo": and see if it works. regards, Sarma. On Thu, Aug 28, 2014 at 12:27 AM, Alan Gauld <alan.ga...@btinternet.com> wrote: > On 27/08/14 14:40, Jake wrote: > >> To whom it may concern, >> My name is Jake and I have recently started the GCSE computing course >> with school. >> > > answera = input() >> if answera == ["Oslo" or "oslo"]: >> > > This doesn't do what you think it does. > > ["Oslo" or "oslo"] is a list > > "Oslo" or "oslo" is the content of the list and > is a boolean expression which evaluates to True. > (Each non-empty string is considered True by Python) > > So your 'if' line looks to Python like: > > if answera == [True]: > > But answera is a string so it will never equal a list > with a single boolean value so you go to the else > clause. > > A better way to do what you want is to convert the input > to lowercase using the string lower() method and compare > that to the string you want, like so: > > if answera.lower() == "oslo": > > If you need to check multiple possible answers you can use > a list of strings and the 'in' operator like this: > > if answera.lower() in ['amsterdam', 'london', 'oslo']: > > HTH > -- > Alan G > Author of the Learn to Program web site > http://www.alan-g.me.uk/ > http://www.flickr.com/photos/alangauldphotos > > > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > https://mail.python.org/mailman/listinfo/tutor >
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