Alex,
Thanks for taking this one step further! I do appreciate it... +1
On Fri, Aug 29, 2014 at 3:48 PM, Alex Kleider <aklei...@sonic.net> wrote:
> On 2014-08-29 12:17, Derek Jenkins wrote:
>>
>> Hi everybody,
>>
>> I have a list that I want to go through and finally print a total
>> count of particular items. In this case, I want to print the result of
>> how many A's and B's are in the list.
>>
>> honor_roll_count = 0
>> student_grades = ["A", "C", "B", "B", "C", "A", "F", "B", "B", "B", "C",
>> "A"]
>>
>> for grades in student_grades:
>> honor_roll_count = honor_roll_count + 1
>> if grades == "A" or grades == "B":
>> print honor_roll_count
>>
>> The above code prints 8 lines, each being an entry for which item in
>> the list was either A or B. Again, I'm looking for the result to be
>> the number 8 itself - the total number of instances that A or B occurs
>> in the list.
>
>
> Try the following:
> print("Running Python3 script: 'tutor.py'.......")
>
>
> student_grades = ["A", "C", "B", "B", "C", "A", "F",
> "B", "B", "B", "C", "A"]
>
> grades = {}
>
> for grade in student_grades:
> grades[grade] = grades.get(grade, 0) + 1
>
> for grade in sorted(grades.keys()):
> print("'{}': {}".format(grade, grades[grade]))
>
> If you are using Python 2, I believe the get method is called something
> else; you can look it up if need be.
>
>
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
https://mail.python.org/mailman/listinfo/tutor
