Hello,
take a look at argparse library.
-------
import argparse
parser = argparse.ArgumentParser(description="My prgoram")
parser.add_argument('-y', '--y', help="Y value", required=True)
parser.add_argument('-x', '--x', help="X value", required=True)
def main(x=1, y=2):
print x
print y
if __name__ == '__main__':
args = parser.parse_args()
main(x=args.x, y=args.y)
Enjoy!
Lukas
On 10/30/2014 03:01 PM, Robert Sokolewicz wrote:
I have a function with optional arguments x, y and I would like to
pass y or z using a named variable through the command line. Inside a
python script main(y=3) would work, but I have trouble passing y=3 as
an argument in command line.
I have tried the following:
----
import sys
def main(x=1, y=2):
print x
print y
if __name__ == '__main__':
main(*sys.argv[1:])
-----
from my terminal I get:
$ python script.py
1
2
$ python script.py y=3
y=3
2
whereas I would like the following to happen:
$ python script.py y=3
1
3
Is this doable in any convenient way?
thanks in advance!
-Robert
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
https://mail.python.org/mailman/listinfo/tutor
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
https://mail.python.org/mailman/listinfo/tutor
