would this work?
>>>
a="fe01b84100000000000000002756fe02fe01b94100000000000000006239fe02fe01ba410000000000000000ad88fe02fe01bb410000000000000000e8e7fe02fe01bc41000000000000000012fbfe02fe01bd4100000000000000005794fe02"
>>> b=a.replace('fe02fe01','fe02\nfe01').split('\n')
>>> for c in b:
... print ' '.join([c[i:i+2] for i in range(0, len(c), 2)])
...
fe 01 b8 41 00 00 00 00 00 00 00 00 27 56 fe 02
fe 01 b9 41 00 00 00 00 00 00 00 00 62 39 fe 02
fe 01 ba 41 00 00 00 00 00 00 00 00 ad 88 fe 02
fe 01 bb 41 00 00 00 00 00 00 00 00 e8 e7 fe 02
fe 01 bc 41 00 00 00 00 00 00 00 00 12 fb fe 02
fe 01 bd 41 00 00 00 00 00 00 00 00 57 94 fe 02
On Wed, Dec 3, 2014 at 12:18 PM, shweta kaushik <[email protected]>
wrote:
> Hi,
>
> I need help for doing this task. I know it will be simple but I am not
> able to do it.
>
>
> output_message_packet=
> fe01b84100000000000000002756fe02fe01b94100000000000000006239fe02fe01ba410000000000000000ad88fe02fe01bb410000000000000000e8e7fe02fe01bc41000000000000000012fbfe02fe01bd4100000000000000005794fe02
>
> I want to split this into separate message packets like this:
> fe01b84100000000000000002756fe02
> fe01b94100000000000000006239fe02
> fe01ba410000000000000000ad88fe02
> fe01bb410000000000000000e8e7fe02
> fe01bc41000000000000000012fbfe02
> fe01bd4100000000000000005794fe02
>
> After this I want to split this into bytes:
> fe 01 b8 41 00 00 00 00 00 00 00 00 27 56 fe 02
>
> Please help me with code for how to do this.
>
> Thanks in advance.
>
> Regards,
> Shweta
>
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