sorry, just me being stupid :P should have read closely what the problem was
On Wed, Feb 4, 2015 at 12:54 PM, Raúl Cumplido <raulcumpl...@gmail.com>
wrote:
> I think you want to use combinations_with_replacement:
>
> >>> var = ['a', 'b', 'c', 'd', 'e']
>
> >>> length=int(raw_input("enter the length of random letters you need "))
> enter the length of random letters you need 2
>
> >>> length
> 2
>
> >>> from itertools import combinations_with_replacement
>
> >>> [''.join(s) for s in combinations_with_replacement(var, 2)]
> ['aa',
> 'ab',
> 'ac',
> 'ad',
> 'ae',
> 'bb',
> 'bc',
> 'bd',
> 'be',
> 'cc',
> 'cd',
> 'ce',
> 'dd',
> 'de',
> 'ee']
>
> On Wed, Feb 4, 2015 at 12:38 PM, Alan Gauld <alan.ga...@btinternet.com>
> wrote:
>
>> On 04/02/15 09:46, Suresh Kumar wrote:
>>
>> print var
>>>>>>
>>>>> ['a', 'b', 'c', 'd', 'e']
>>>
>>
>> the user gave two so code should be like this
>>>
>>>> for i in itertools.product(var,var):
>>>>>>
>>>>> print i[0]+i[1]
>>>
>>
>> output of code should be like this
>>> aa
>>> ab
>>>
>> ...
>>
>>> ee
>>>
>>
>> based on the user given input of length i need to add var in for loop
>>> if 3 given
>>>
>>>> for i in itertools.product(var,var,var):
>>>>>>
>>>>> print i[0]+i[1]+i[2]
>>>
>>
>> OK, So the question is how to pass n copies of var to product()?
>>
>> You could do it by enclosing var in an outer list or tuple, then
>> unpacking the result in the call to product():
>>
>> Untested...
>>
>> for i in itertools.product(*((var,) * n)):
>> print ''.join(i)
>>
>> Does that work?
>>
>>
>>
>> --
>> Alan G
>> Author of the Learn to Program web site
>> http://www.alan-g.me.uk/
>> http://www.amazon.com/author/alan_gauld
>> Follow my photo-blog on Flickr at:
>> http://www.flickr.com/photos/alangauldphotos
>>
>>
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>
>
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