On 02/14/2015 04:07 AM, Steven D'Aprano wrote:
On Sat, Feb 14, 2015 at 03:17:28AM +0000, steve10br...@comcast.net wrote:
Hi all,
I was playing with Python tonight and created a simple program that
outputs numbers counting up then counting down all on the same
terminal line. The code is as follows:
#------------------------------------------------------------
a = 320000 #number to count up to
for i in range (a):
print i, '\r',
for i in range ((a-1),0,-1):
print i, '\r',
#------------------------------------------------------------
It works as desired. However, I was trying to figure out a way to make
it more concise but cannot see a way since the 'range' parameters must
be integers (no functions allowed?).
Parameters to range can be anything which evaluates to integers, but
I'm not sure how that will help you. Also, in Python 2 xrange is a
little more efficient than range.
How's this?
a = 320000
counts = (xrange(a), xrange(a-1, 0, -1))
for counter in counts:
for i in counter:
print i, '\r'
BUT I'm not sure why you are worried about making it more concise when
your code doesn't do what you want, as far as I can tell. You want the
counter to be written on the same line, not 640 thousand lines, but when
I try it, I get each number written to a different line.
That's probably because you've dropped the trailing comma that the OP
used in the print statements.
Try this instead:
import sys
a = 320000
counts = (xrange(a), xrange(a-1, 0, -1))
for counter in counts:
for i in counter:
sys.stdout.write(str(i) + '\r')
sys.stdout.flush()
--
DaveA
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