On 11/03/15 21:26, Wibble wrote:
def user_choice(question, low, high, step = 1):
"""Define user choice"""
choice = None
while choice not in range(low, high, step):
choice = int(input(question))
return choice
If user enters a string rather than a number it creates this error
Traceback (most recent call last):...
choice = int(input(question))
ValueError: invalid literal for int() with base 10: 'd'
How do I make it show a message to users saying only numbers excepted
and then the loop continues?
Use a try/except construct inside your while loop.
Something like (untested):
def user_choice(question, low, high, step = 1):
"""Define user choice"""
choice = None
while choice not in range(low, high, step):
try:
choice = int(input(question))
except ValueError:
print("You must enter a number between ",low," and ", high)
return choice
HTH
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.amazon.com/author/alan_gauld
Follow my photo-blog on Flickr at:
http://www.flickr.com/photos/alangauldphotos
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