Thanks I will look into these. The data going in is a list like 
this:['broadcast', '"d8on"', 'broadcast', '"d11on"']

With the output beng something like this.

lst_0 = ['broadcast', '"d8on"']

lst_0 = ['broadcast', '"d11on"']

I have managed to use a dictionary as advised in a post on StackOverflow; not 
quite completed it as I am overwriting my lists each time. From your experience 
is it better to pursue the dictionary route or the zip tuple option. I am in 
python2.7

----------------------------------------
> Date: Tue, 31 Mar 2015 10:30:04 -0400
> From: da...@davea.name
> To: tutor@python.org
> Subject: Re: [Tutor] Dynamic naming of lists
>
> On 03/31/2015 10:00 AM, Ian D wrote:
>> Hi
>>
>> I have a list that I am splitting into pairs of values. But the list is 
>> dynamic in size. It could have 4 values or 6 or more.
>>
>> I originally split the list into pairs, by using a new list and keep a pair 
>> in the old list by just popping 2 values. But if the list is longer than 4 
>> values. I cannot do this. I can only envision I would need to dynamically 
>> create lists. How would I do this?
>>
>> while returned_list_of_items:
>> for i in range(1):
>> new_list.append(returned_list_of_items.pop(0)) #pop first value and append
>> new_list.append(returned_list_of_items.pop(0)) #pop second value and append
>>
>
> It'd really be a lot clearer if you gave one or more examples of input
> and output data. Like you want list [1,2,3,4] to become [ (1,2), (3,4) ]
>
> I'll guess you want a list of two-tuples. It so happens there's a nice
> built-in for the purpose.
>
> https://docs.python.org/3/library/functions.html#zip
>
>>>> s = [1,2,3,4,5,6,7,8]
>>>> list(zip(*[iter(s)]*2))
> [(1, 2), (3, 4), (5, 6), (7, 8)]
>
>
>
> --
> DaveA
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