On Tue, Mar 31, 2015 at 3:32 PM, Dave Angel <da...@davea.name> wrote: > On 03/31/2015 04:23 PM, boB Stepp wrote: >> >> The following behavior has me stumped: >> >> Python 2.7.8 (default, Jun 30 2014, 16:03:49) [MSC v.1500 32 bit >> (Intel)] on win32 >> Type "copyright", "credits" or "license()" for more information. >>>>> >>>>> L = ['#ROI:roi_0', '#TXT:text_0', '#1:one^two^three'] >>>>> for i, item in enumerate(L): >> >> subitems = item.split(':') >> if subitems[0] == '#ROI': >> print subitems[1] >> if subitems[0] == '#TXT': >> print subitems[1] >> if subitems[0] == '#1' or '#2': > > > I think what you meant here was: > if subitems[0] == "#1" or subitems[0] == "#2": > >> print subitems[1] > > > Study the first expression and see if you can figure out what the difference > is. If it's not clear, then make a simpler program just to test a compound > if, and we'll all talk about it.
Yeah, your version evaluates to "False or False", which is what I wanted, but my version didn't. >> BTW, I copied and pasted the above into my Gmail window, but it >> removed the indentation that was present in the interpreter. I added >> spaces manually to get it appear as it did in the interpreter. Anyone >> know why Gmail does that to my copy and paste? >> > > Buggy, I guess. Why not use a program like Thunderbird, which is free and > available on most PC operating systems? > > (Unfortunately, it's not on Android) This is on my TODO list! I had started an earlier thread looking for a Gmail replacement if you recall. I just haven't gotten riled enough by Gmail to make the switch, but I am oh, so close! -- boB _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor