On 05/05/2015 12:29 AM, Brandon D wrote:
Hello tutors,
I'm having trouble understanding, as well as visualizing, how object
references work in the following situation. For demonstration purposes I
will keep it at the most rudimentary level:
x = 10
x = x ** x
If my knowledge serves me correctly, Python destroys the value once
reassigned. So, how does x = x + 1 work if it's destroyed before it can
be referenced? The only solution I came up with is that the two operands
are evaluated before storing it in the variable, consequently replacing the
original value of 0.
It's not destroyed before it's referenced. The ten-object is destroyed
(or may be, depending on optimizations and such) when nothing is bound
to it. That happens just after the new object is bound to x.
it may be interesting to put some simple statements into a function, and
use dis.dis on that function.
import dis
def myfunc():
x = 10
x = x ** x
dis.dis(myfunc)
--
DaveA
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
https://mail.python.org/mailman/listinfo/tutor
