I noticed that if I call a function that throws an error, I can catch it
from the caller, instead of catching it in the function. Is this is what is
known as "errors bubbling up?" Also, is this how you're supposed to do it?
*** Python 3.4.3 (v3.4.3:9b73f1c3e601, Feb 24 2015, 22:43:06) [MSC v.1600
32 bit (Intel)] on win32. ***
'''Print a table of random numbers, given min, max, rows, and columns'''
from random import randint
def make_table(minimum, maximum, rows, columns):
for row in range(rows):
print()
for column in range(columns):
print(randint(minimum, maximum), end = ' ')
def get_input():
inp = input("Enter minimum, maximum, rows, and columns, separated by
commas: ")
inps = inp.split(',')
try:
minimum = int(inps[0])
maximum = int(inps[1])
rows = int(inps[2])
columns = int(inps[3])
return minimum, maximum, rows, columns
except ValueError as err:
print("non-integer entered", err)
return None
except IndexError as err:
print("You didn't enter enough values.", err)
return None
vals = get_input()
if vals:
minimum, maximum, rows, columns = vals
try:
make_table(minimum, maximum, rows, columns)
except ValueError as err: # CATCH FUNCTION ERROR HERE INSTEAD OF IN
FUNCTION
print("Enter min before max.")
else:
print('Nothing to do.')
--
Jim
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