Sorry, the interpreter uses colour which is why some code is missing. Here
is the text version of my code:
def odd_or_even():
X=input("Enter the number which you want to check for odd and even: ")
try:
number=int(X)
print("The number %s is ODD."%(number)if number%2!=0 else "The
number %s is EVEN."%(number))
except ValueError:
print("Invalid input")
On Thu, Jun 25, 2015 at 2:06 PM, Whom Isac <wombing...@gmail.com> wrote:
> For abhijeet...@yahoo.in:
> I had posted few solution to your question before but unfortunately they
> were sent to Alan Gauld mail because I am not used to the tutor@python.org
> mail system.
> Here is the code that will work:
> ""ODD/EVEN finder:"""
>
>
> def odd_or_even():
> X=input("Enter the number which you want to check for odd and even: ")
> try:
> number=int(X)
> print("The number %s is ODD."%(number)if number%2!=0 else "The number
> %s is EVEN."%(number))
> except ValueError:
> print("Invalid input")
>
>
> On Thu, Jun 25, 2015 at 1:59 PM, Whom Isac <wombing...@gmail.com> wrote:
>
>> *def *odd_or_even():
>> X=input("Enter the number which you want to check for odd and even: ")
>> number=int(X)
>> print("The number %s is ODD."%(number) *if *number%2!=0 *else *"The
>> number %s is EVEN."%(number))
>>
>> On Thu, Jun 25, 2015 at 1:53 PM, Whom Isac <wombing...@gmail.com> wrote:
>>
>>> Hi, abhijeet...@yahoo.in:
>>> there is four or five ways to do your question as I had done one for you
>>> before. As you could tell there are also a shorter version to do this,
>>> using list comprehension method. I would recommend you to use codeacademy
>>> if you are not sure. Here is a quickest way for the ODD/EVEN list
>>> comprehension. Both works the same way too.
>>>
>>>
>>> def odd_or_even():
>>> X=input("Enter the number which you want to check for odd and even: ")
>>> number=int(X)
>>> print("The %s is ODD"%(number)if number%2!=0 else "The %s is
>>> EVEN"%(number))
>>>
>>>
>>> On Thu, Jun 25, 2015 at 1:47 PM, Whom Isac <wombing...@gmail.com> wrote:
>>>
>>>> Yes, I agree with Alan Gauld.
>>>>
>>>> For Gupta's case:
>>>>
>>>> if you wanted to get your point across you should mention your
>>>> intention and could have posted any error message along with your code.
>>>> Because, your question is vague and if the original script of the code had
>>>> been posted, that would have been a huge help.
>>>>
>>>> And, for abhijeet...@yahoo.in:
>>>>
>>>> Is that any section of the function?? If it is then please, repost your
>>>> question with full definition of the function and please read python's rule
>>>> to indentation, maybe that's where the error is. However, as you said your
>>>> function execute normally, therefore I am assuming you misunderstood how
>>>> while loops works. Note for you: I don't think there would be any exception
>>>> raise for ValueError in your code so try: and except: method would not be
>>>> necessary..
>>>>
>>>> For a simple odd and even finder I would try to do this:
>>>>
>>>> """ODD or EVEN Finder: """
>>>>
>>>> def odd_or_even():
>>>> X=input("Enter the number which you want to check for odd and even: ")
>>>> number=int(X)
>>>> while True:
>>>> if number%2==0:
>>>> print("The number ", number, " is Even.")
>>>> #number +=1
>>>> else:
>>>> print("The number ",number, " is Odd")
>>>> break
>>>> pass
>>>>
>>>>
>>>>
>>>>
>>>> On Thu, Jun 25, 2015 at 2:27 AM, Alan Gauld <alan.ga...@btinternet.com>
>>>> wrote:
>>>>
>>>>> On 24/06/15 13:58, abhijeet...@yahoo.in wrote:
>>>>>
>>>>>> Hey guys can anybody tell me what's wrong with this code: The code is
>>>>>> below?
>>>>>>
>>>>>
>>>>> Please in future
>>>>> 1) start a new thread with a new post, do not hijack somebody else's
>>>>> query. It messes up the archive and threaded mail/newsreaders
>>>>>
>>>>> 2) Use plain text for posting code, your post is all messed up by the
>>>>> mail system so we can't see the code clearly. It is all on one line...
>>>>>
>>>>> Actually the point is that when we put "34h4" type of value
>>>>>>
>>>>> > it's an valueerror but here no handling is been performed
>>>>>
>>>>> The handling only happens if it occurs inside a try block. It looks as
>>>>> if your type conversion (int(...)) happens outside the try block.
>>>>> The error is raised by the type conversion.
>>>>>
>>>>> while 1: number=int(input("Enter the number which u want to check
>>>>>> for odd and even :")) try : if number%2==0:
>>>>>> print("The
>>>>>> number",number ," is Even") else: print("The number
>>>>>> ",number ," is Odd") except ValueError:
>>>>>> print("Invalid
>>>>>> Input")
>>>>>>
>>>>>
>>>>> Finally, handling an error by simply printing a bland error message
>>>>> is usually not a good idea. You effectively hide a lot of valuable
>>>>> debugging information. You would be better to just let Python print
>>>>> out its usual, much more helpful, error message.
>>>>>
>>>>> (The exception is where it's the top level of an end-user program
>>>>> where the Python trace might scare the users. But that should only
>>>>> be after you have thoroughly debugged it and handled most of the
>>>>> likely problem scenarios, and hopefully logged the error data
>>>>> into a logfile or sent it as an email to your support desk.)
>>>>>
>>>>>
>>>>> --
>>>>> Alan G
>>>>> Author of the Learn to Program web site
>>>>> http://www.alan-g.me.uk/
>>>>> http://www.amazon.com/author/alan_gauld
>>>>> Follow my photo-blog on Flickr at:
>>>>> http://www.flickr.com/photos/alangauldphotos
>>>>>
>>>>>
>>>>> _______________________________________________
>>>>> Tutor maillist - Tutor@python.org
>>>>> To unsubscribe or change subscription options:
>>>>> https://mail.python.org/mailman/listinfo/tutor
>>>>>
>>>>
>>>>
>>>
>>
>
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