On 18/09/15 16:41, marcus lütolf wrote:
s = ['ab','ac','bc','ad','ae','de']
for startlist in itertools.combinations(s, 3):
How can I concatenate the 20 lists in oder to get one count for each of the
items in s , for example 10 for 'ab'?
If I understand you correctly, something like this:
>>> counts = {'ab':0,'ac':0,'bc':0,'ad':0,'ae':0,'de':0}
>>> for combo in it.combinations(counts.keys(),3):
... for pair in combo:
... counts[pair] += 1
...
>>> counts
{'ac': 10, 'ab': 10, 'ae': 10, 'ad': 10, 'bc': 10, 'de': 10}
Is that what you want?
--
Alan G
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