On 2015-10-28 08:09, Vusa Moyo wrote:
Hi Guys,
I've written a script to remove vowels from a string/sentence.
the while loop I'm using below is to take care of duplicate vowels
found in
a sentence, ie
anti_vowel('The cow moos louder than the frog')
It works, but obviously its messy and n00by. Any suggestions on how I
can
write this code better?
----
def anti_vowel(text):
vowel = ['a', 'e', 'i', 'o', 'u']
VOWEL = ['A', 'E', 'I', 'O', 'U']
manip = []
for i in text:
manip.append(i)
fufu = 0
#
while fufu < 16:
for x in vowel:
if x in manip:
manip.remove(x)
for y in VOWEL:
if y in manip:
manip.remove(y)
fufu = fufu + 2
strong = ''.join(manip)
return strong
----
Thanks - Vusa
This struck me as a good place to utilize list comprehension.
VOWELS = 'aeiouAEIOU'
def remove_chars(s, chars2remove=VOWELS):
"""Returns the string s but without any of
the characters found in chars2remove.
If given only one parameter, defaults to removing vowels.
"""
s_as_list = [char for char in s]
without_chars2remove = [
char for char in s_as_list if char not in chars2remove]
# print(s_as_list) # for testing
# print(without_chars2remove) # ditto
return "".join(without_chars2remove)
if __name__ == "__main__":
print(remove_chars(
'The cow moos louder than the frog'))
There may be some other constructs (the string join method on the empty
string)
to which you haven't yet been exposed.
Confession: I'm submitting it probably as much to garner comments from
the
pundits as to help you.
cheers,
Alex
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