On 19/11/2015 15:31, Greg Christian wrote:
I’m trying to sort a list of tuples based on the second item in the tuple. When I run this in IDLE I get the correct output; however, when running inside of a program, and calling the counter() function, sorted does not seem to work? Any ideas on why this works in IDLE and not in program would be appreciated. Thank You.def getKey(item): return item[1] def counter(): L = [("baby", 9999), ("aeuron", 100), ("pablo", 1234)] sorted(L, key=getKey) print ("L = ", L) OUTPUTS THIS (when calling counter inside of program): L = [('baby', 9999), ('aeuron', 100), ('pablo', 1234)] OUTPUTS THIS (when running with IDLE – desired output): [('aeuron', 100), ('pablo', 1234), ('baby', 9999)]
Your use of sorted achieves precisely nothing as you discard the return value. Either save the value or use the built-in sort which works in place.
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