On 11/21/2015 7:05 AM, Aadesh Shrestha wrote:
I am currently taking challenges on codewars.
Problem: Square Every Digit
is there a better solution than this which requires less code?
def square_digits(num):
arr = []
list = []
while(num !=0):
temp = num%10
num = num /10
arr.insert(0, temp)
for i in arr:
list.append( i*i)
str1 = ''.join(str(e) for e in list)
return int(str1)
************************
Aadesh Shrestha
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"Better" is somewhat subjective, but "less code" is not so much so:
def square_digits(num):
try:
return int(''.join((str(int(n)**2) for n in str(int(num)))))
except ValueError:
return 0
The "str(int(num))" could be shortened to "str(num)", also, but I liked
being able to accept any argument that could be converted to an int, and
also raising the ValueError before looping .
Have fun at codewars
Nathan Hilterbrand
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