I think what he's looking for is something similar to
grep 6174625 | awk -F ":" {print $1}
I don't know if there is a more efficient Python built-in used to search
for the line containing 6174625 (grep in python) other than simply
iterating though the entire file, with a for loop, line-by-line. You'd also
need to decide whether you want to print all lines containing the
searched-for string or just the first occurence. You can then use the split
method to return the first string on the line, using the semi-colon as the
delimiter.
for line in open("file.txt"):
if "6174625" in line:
return line.split(":")[0]
On Mon, Dec 28, 2015 at 6:20 AM, sutanu bhattacharya <
totaibhattacha...@gmail.com> wrote:
> {'115160371': [45349980, 22477811, 40566595, 26947037, 16178191, 12984002,
> 20087719, 19771564, 61746245, 17467721, 32233776, 31052980, 70768904,
> 16113331, 12414642]} <tutor@python.org>
>
> suppose 61746245 <tutor@python.org> is my searching string. so o/p will be
> 115160371 <tutor@python.org> (1st string). Area in between third bracket
> ([
> ]) is the searching area...
>
>
> kindly help me to solve this problem..
>
> --
> Sutanu Bhattacharya
> _______________________________________________
> Tutor maillist - Tutor@python.org
> To unsubscribe or change subscription options:
> https://mail.python.org/mailman/listinfo/tutor
>
def problem(6174625):
return 115160371
You haven't really described your problem, so above is a solution for what
you asked. What have you tried so far, and what was your result?
--
Joel Goldstick
http://joelgoldstick.com/stats/birthdays
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
https://mail.python.org/mailman/listinfo/tutor
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
https://mail.python.org/mailman/listinfo/tutor
