Oscar Benjamin wrote:
> On 28 April 2016 at 02:02, Kanika Murarka <murarkakan...@gmail.com> wrote:
>> Thanks Oliver and Alex, I didnt know about these commands :D
>>
>> Oliver,
>> When i typed
>> print filename
>> print sys.executable
>> print sys.prefix
>> print os.path.split(sys.prefix)[-1]
>>
>> my output was
>>
>> /home/kanikaa/pydsa7/venv/lib/python2.7/site-
packages/ipython_genutils/tests/test_tempdir.py
>> /usr/bin/python
>> /usr
>> usr
>> but i want to know weather file belongs to 'venv' folder or not.
>
> You can check if the 'venv' folder is part of a path using:
>
> import os.path
>
> dirpath = os.path.dirname(filename)
> dirnames = []
> while dirpath:
> dirpath, dirname = os.path.split(dirpath)
> dirnames.append(dirname)
>
> if 'venv' in dirnames:
> # do whatever
>
> But how would you know that 'venv' is the name of a virtual
> environment folder? A virtual environment folder can be called
> anything.
>
> You can write some code to test if a particular path represents the
> base directory of a virtual environment but I expect it would probably
> be fragile. Without knowing why you want to do this I suggest that you
> might want to find a different general approach to your real problem.
You could look for bin/activate. Yes, it's fragile, but in practice it might
be good enough:
import pathlib
import sys
path = sys.argv[1]
for p in pathlib.Path(path).parents:
if p.joinpath("bin/activate").is_file():
print("potential virtual environment:")
print(p)
break
$ python3 check_venv.py /home/nemo/virt/docopt/lib/python2.7/site-
packages/docopt.py
potential virtual environment:
/home/nemo/virt/docopt
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