Thanks, everyone, for your help.
The objective was to extract all words from each line and place them in a
list IF they didn't already exist in it.
I sorted it out by adding little bits of everyone's suggestions.
Here's the code that fixed it.
fname = raw_input('Enter file name:\n')
try:
fhand = open(fname)
except:
print 'File cannot be found or opened:', fname
exit()
lst = list()
for line in fhand:
words = line.split()
for word in words:
if word in lst:
continue
else:
lst.append(word)
lst.sort()
print lst
I named the file WordExtract.py since it does just that. :)
*Warm regards,*
*Olaoluwa O. Thomas,*
*+2347068392705*
On Thu, Jun 2, 2016 at 6:44 PM, Steven D'Aprano <st...@pearwood.info> wrote:
> On Thu, Jun 02, 2016 at 06:05:43PM +0100, Olaoluwa Thomas wrote:
>
> > fname = raw_input('Enter file name:\n')
> > try:
> > fhand = open(fname)
> > except:
> > print 'File cannot be found or opened:', fname
> > exit()
> > lst = list()
> > for line in fhand:
> > words = line.split()
> > #print words (this was a test that a portion of my code was working)
> > lst.append(words)
>
> If you printed words, you should have seen that it was a list.
>
> If you append a list to a list, what do you get? At the interactive
> prompt, try it:
>
>
> py> L = [1, 2, 3]
> py> L.append([4, 5, 6])
> py> L
> [1, 2, 3, [4, 5, 6]]
>
>
> Append takes a single argument, and adds it *unchanged* to the end of
> the list.
>
> What you want is the extend method. It takes a list as argument, and
> appends each item individually:
>
>
> py> L.extend([7, 8, 9])
> py> L
> [1, 2, 3, [4, 5, 6], 7, 8, 9]
>
>
> But if you didn't know about that, you could have done it the
> old-fashioned way:
>
> lst = list()
> for line in fhand:
> words = line.split()
> for word in words:
> lst.append(word)
>
>
>
> --
> Steve
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