On Thu, Jan 05, 2017 at 08:29:33AM -0500, S. P. Molnar wrote: [...] > To change the frequency to wave length I did the following: > > > p=1/1e7 > wave_length = p*np.array(frequency) > > (The relationship between wavelength and frequency is: wavelength = > 1.0e7/frequency, where 1e7 is the speed of light) > > > Apparently whhat I have managed to do is divide each element of the > frequency list by 1/1e7.
Indeed :-) This is a matter of arithmetic: Let p = 1/x then p*f = (1/x)*f = f/x So you have divided each frequency by x, namely 1e7. What you want is: x/f which divides x (1e7) by the frequency. The interactive interpreter is very good for exploring simple questions like this. If you need help starting the interactive interpreter, please ask, although I haven't used Spyder for many years and I'm not familiar with it. But in the regular Python interpreter, I can do this: py> import numpy as np py> data = np.array([1, 2, 3]) py> data array([1, 2, 3]) py> factor = 1/10.0 py> factor*data array([ 0.1, 0.2, 0.3]) py> factor/data array([ 0.1 , 0.05 , 0.03333333]) (lines starting with "py>" is the code I have typed). So to get the result you want, you should be able to do this: wave_length = 1e7/np.array(frequency) -- Steve _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor