Many thanks! On 25-03-17 11:17, Alan Gauld via Tutor wrote:
On 25/03/17 10:01, Peter O'Doherty wrote:def myFunc(num): for i in range(num): print(i) print(myFunc(4)) 0 1 2 3 None #why None here?Because your function does not have an explicit return value so Python returns its default value - None. So the print() inside the function body prints the 0-3 values then the function terminates and returns the (default) None to your top level print.def myFunc(num): for i in range(num): return i print(myFunc(4)) 0 #why just 0?Because return always returns from the function immediately. So you call the function, it enters the loop, sees the return for the first element and exits. The print() then prints that returned value. The preferred method to do what I think you were expecting is to build a list: def anotherFunction(num): result = [] for i in range(num): result.append(i) return result Which is more concisely written using a list comprehension but that would hide the general point - that you should accumulate results in a collection if you want to return more than a single value. To print the result you would typically use the string.join() method: print(' '.join(anotherFunction(4))
//============================= // Peter O'Doherty // http://www.peterodoherty.net // m...@peterodoherty.net //============================= _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
