On Mon, 24 Apr 2017 09:24:55 +1000
Phil <phil_...@bigpond.com> wrote:
> On Sun, 23 Apr 2017 09:39:54 +0200
> Sibylle Koczian <nulla.epist...@web.de> wrote:
>
> > Am 20.04.2017 um 14:43 schrieb Alan Gauld via Tutor:
> > > Its not too bad you can map the large 9x9 table to the smaller
> > > units using divmod()
> > >
> > > So the 7th element becomes
> > > divmod(7) -> 2,1
> > >
> >
> > Should be divmod(7, 3), shouldn't it?
>
> Thanks Sibylle, I eventually stumbled upon the answer using my usual
> trial-and-error method. The 3, as in the number of cells, was the key.
Actually, that's not correct either.
Say I want the 7th cell in the first line of a 9 x 9 grid, that would be x = 7,
y = 1. divmod(7,1) = 2,1 or the first cell in grid 3. So far so good.
Another example, x = 4, y = 3. divmod(4,3) = 1,1. What I need here is grid 2 x
= 1 and y = 3.
Further complications are, arrays, or lists in Python, start a 0 and divmod may
not be the answer because divide by 0 is not possible. Making adjustments for
these two possibilities has resulted in complicated code that does give the
desired result. Of course, I may have misunderstood the intention of Alan's
mapping method.
So, what I need is a function to map from a 9 x 9 grid to a cell in a 3 x 3
grid.
My feeble simplified attempt is as follows:
def map_cell(x,y):
return divmod(x,y)
while(True):
x,y = input().split(" ")
print (map_cell(int(x), int(y)))
--
Regards,
Phil
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
https://mail.python.org/mailman/listinfo/tutor
