On 25/12/17 03:46, anish singh wrote:
However, I am stuck. I have below code which is not working.
I don't know how to achieve this programmatically: sorted by the
number of occurrences in a descending order. If two or more words
have the same count, they should be sorted
alphabetically (in an ascending order).
There is probably way to write a sort function that will
do what I want but personally I'd divide and conquer by
putting the results into two chunks. First I'd have a new
dictionary keyed by the frequency. And the values in each
frequency would be lists sorted alphabetically. So, for
your data, it would look like:
data = {
4:['just'],
3:['practice'],
2:['perfect'],
1:['by','get','makes','you\'ll']
}
#expected:
[["just","4"],["practice","3"],["perfect","2"],["makes","1"],["youll","1"],["get","1"],["by","1"]]
Really? I'd expect:
[["just","4"],["practice","3"],["perfect","2"],["by","1"],["get","1"],["makes","1"],["you'll","1"]]
as I did in the dict above.
HTH
Alan G.
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