On Mon, 26 Feb 2018, Roger Lea Scherer wrote:
""" ensure input is no other characters than digits
sudocode: if the input has anything other than digits
return digits """
....
p = re.compile(r'[^\D]')
I'm not so great at regular expressions, but this regex appears to be
searching for a string that matches anything in the class start-of-string
of non-digit.
"[...]" says, look for anything in this set of characters; and you have
two things:
^ : start-of-string
\D : any non-digit
Instead of looking fo re xcaprions, I would look for what you *do* want.
this regex should do it for you:
r'^\d+$'
This is looking for a start-of-string ("^"); then a digit ("\d") that
occurs at least once (the "+" qualifier); then an end-of string ("$").
In other words, one or more digits, with nothing else before or after.
Here's a simple looping test to get you started (ignore the "from
__future__" line; I'm running Python 2):
from __future__ import print_function
import re
p = re.compile(r'^\d+$')
test_data = ["4jkk33", "4k33", "4jjk4", "4334", "4","44", "444", ""]
for thing in test_data:
m = p.match(thing)
if m is None:
print("not all digits:", thing)
else:
print("all digits:", thing)
--
Terry Carroll
carr...@tjc.com
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