On Wed, Mar 28, 2018 at 2:09 PM, Roger Lea Scherer <rls...@gmail.com> wrote:
> In one of my lessons I am asked to compare approximations for pi. I got
> everything to work properly and my attempt is successful and matches
> Python's approximation up to 15 digits to the right of the decimal, but I
> suspect I can do this programmatically rather than the repetitious way I
> did.
>
> I tried "for i in range(10):"; then I tried "c += c" so it would be a sum.
> Those attempts did not work. I tried math.fsum and though the documentation
> says it is for iterables I could not get it to work as I desired. I
> received an error that said TypeError: 'float' object is not iterable
>
> I included all the code so I wouldn't neglect any you might need. Can you
> help again?
You are using the formula in the Wikipedia article, right? Mimic in
Python what you are doing by manually. Do something like:
pi_approx = 0.0
for k in range(10):
pi_approx += your formula from the Wikipedia article
print(pi_approx)
You might even want to make a function out of the above so that you
can try iterating over different ending values for k:
def calc_pi(loop_value):
pi_approx = 0.0
for k in range(loop_value):
pi_approx += your formula
return pi_approx
print(calc_pi(10))
You actually had all the pieces mentioned. You just need to put them
together, looping just like you would do if you were calculating by
hand.
HTH!
boB
>
> # compare various approximations of pi
> import math
> import random
>
> # simplest estimate
> a = 22/7
> print(a)
>
> # next simplest
> b = 355/113
> print(b)
>
> # from wikipedia:
> # In 1910, the Indian mathematician Srinivasa Ramanujan found several
> rapidly converging infinite series
> c = (2*math.sqrt(2)/9801) * (((math.factorial(4*0))*(1103+26390*0)) /
> ((math.factorial(0)**4)*(396**(4*0))))
> d = (2*math.sqrt(2)/9801) * (((math.factorial(4*1))*(1103+26390*1)) /
> ((math.factorial(1)**4)*(396**(4*1))))
> e = (2*math.sqrt(2)/9801) * (((math.factorial(4*2))*(1103+26390*2)) /
> ((math.factorial(2)**4)*(396**(4*2))))
> f = (2*math.sqrt(2)/9801) * (((math.factorial(4*3))*(1103+26390*3)) /
> ((math.factorial(3)**4)*(396**(4*3))))
> g = (2*math.sqrt(2)/9801) * (((math.factorial(4*4))*(1103+26390*4)) /
> ((math.factorial(4)**4)*(396**(4*4))))
> h = (2*math.sqrt(2)/9801) * (((math.factorial(4*5))*(1103+26390*5)) /
> ((math.factorial(5)**4)*(396**(4*5))))
> i = (2*math.sqrt(2)/9801) * (((math.factorial(4*6))*(1103+26390*6)) /
> ((math.factorial(6)**4)*(396**(4*6))))
> j = (2*math.sqrt(2)/9801) * (((math.factorial(4*7))*(1103+26390*7)) /
> ((math.factorial(7)**4)*(396**(4*7))))
> k = (2*math.sqrt(2)/9801) * (((math.factorial(4*8))*(1103+26390*8)) /
> ((math.factorial(8)**4)*(396**(4*8))))
> l = (2*math.sqrt(2)/9801) * (((math.factorial(4*9))*(1103+26390*9)) /
> ((math.factorial(9)**4)*(396**(4*9))))
> m = c + d + e + f + g + h + i + j + k + l
> print(1/m)
>
> print(math.pi)
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