> I wrote this code below > I was wondering if there is a shorter, more elegant way to accomplish this > task. > Thanks!
thank you so much everyone! List comprehension is really cool. One thing I like about list comprehension is that you can get a dictionary, tuples or lists as a result by just changing the type of braces. # dictionary colors = ["red", "blue", "white", "yellow"] colors_len = [{color, len(color)} for color in colors] print(colors_len) # tuples colors = ["red", "blue", "white", "yellow"] colors_len = [(color, len(color)) for color in colors] print(colors_len) # lists colors = ["red", "blue", "white", "yellow"] colors_len = [[color, len(color)] for color in colors] print(colors_len) Can you shed some light on when to use which of the above data structures? I assume there is no simple answer to that question, I am still trying to understand the fundamentals of Python (which happens to be my first programming language). Thanks! > animals = ["Dog", "Tiger", "SuperLion", "Cow", "Panda"] > > # step one: convert the animal list into a list of lists > > animals_lol = [] > > for animal in animals: > animal_split = animal.split(",") > animals_lol.append(animal_split) > > # step two: collect the length of each string in a separate list > > animals_len = [] > > for animal in animals: > animals_len.append(len(animal)) > > # step three: append the length of each string to the list of lists > > for a, b in enumerate(animals_lol): > b.append(animals_len[a]) > > print(animals_lol) > > [['Dog', 3], ['Tiger', 5], ['SuperLion', 9], ['Cow', 3], ['Panda', 5]] _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor